3-digit in Reverse

Write a program that user inputs 3-digit number and its output in reverse order.

#include <iostream.h>

#include <conio.h>

void main()

{

int digit,a,b,c,num,rev;

cout<<"Enter a three-digit number: ";

cin>>digit;

a=digit%10;

num=digit/10;

rev=a;

b=num%10;

num=num/10;

rev=(rev*10)+b;

c=num%10;

num=num/10;

rev=(rev*10)+c;

cout<<"\n Orignal number is: "<<digit;

cout<<"\n Reverse number is: "<<rev;

getch();

}